13111211312231 has 4 divisors (see below), whose sum is σ = 13159951875000. Its totient is φ = 13062470749464.

The previous prime is 13111211312203. The next prime is 13111211312257. The reversal of 13111211312231 is 13221311211131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 13111211312231 - 2³⁰ = 13110137570407 is a prime.

It is a super-2 number, since 2×13111211312231² (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 13111211312197 and 13111211312206.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111211312261) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 24370280981 + ... + 24370281518.

It is an arithmetic number, because the mean of its divisors is an integer number (3289987968750).

Almost surely, 2^{13111211312231} is an apocalyptic number.

13111211312231 is a deficient number, since it is larger than the sum of its proper divisors (48740562769).

13111211312231 is an equidigital number, since it uses as much as digits as its factorization.

13111211312231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 48740562768.

The product of its digits is 216, while the sum is 23.

Adding to 13111211312231 its reverse (13221311211131), we get a palindrome (26332522523362).

The spelling of 13111211312231 in words is "thirteen trillion, one hundred eleven billion, two hundred eleven million, three hundred twelve thousand, two hundred thirty-one".