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13111213103 is a prime number
BaseRepresentation
bin11000011010111110…
…10011110000101111
31020211202001122011022
430031133103300233
5203322432304403
610005002444355
7642623321042
oct141537236057
936752048138
1013111213103
115618a3550a
12265ab036bb
13130c440281
148c5438c59
1551b0bdd38
hex30d7d3c2f

13111213103 has 2 divisors, whose sum is σ = 13111213104. Its totient is φ = 13111213102.

The previous prime is 13111213099. The next prime is 13111213177. The reversal of 13111213103 is 30131211131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13111213103 - 22 = 13111213099 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111219103) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555606551 + 6555606552.

It is an arithmetic number, because the mean of its divisors is an integer number (6555606552).

Almost surely, 213111213103 is an apocalyptic number.

13111213103 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111213103 is an equidigital number, since it uses as much as digits as its factorization.

13111213103 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 13111213103 its reverse (30131211131), we get a palindrome (43242424234).

The spelling of 13111213103 in words is "thirteen billion, one hundred eleven million, two hundred thirteen thousand, one hundred three".