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131112131335 = 589294634003
BaseRepresentation
bin111101000011011100…
…1000101101100000111
3110112102102121101000021
41322012321011230013
54122004201200320
6140122044000011
712321036504523
oct1720671055407
9415372541007
10131112131335
115067141a939
12214b1230007
13c496412203
1464bb084d83
1536257e3daa
hex1e86e45b07

131112131335 has 8 divisors (see below), whose sum is σ = 159102362160. Its totient is φ = 103711168704.

The previous prime is 131112131323. The next prime is 131112131341. The reversal of 131112131335 is 533131211131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 131112131335 - 25 = 131112131303 is a prime.

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 147316557 + ... + 147317446.

It is an arithmetic number, because the mean of its divisors is an integer number (19887795270).

Almost surely, 2131112131335 is an apocalyptic number.

131112131335 is a deficient number, since it is larger than the sum of its proper divisors (27990230825).

131112131335 is an equidigital number, since it uses as much as digits as its factorization.

131112131335 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 294634097.

The product of its digits is 810, while the sum is 25.

Adding to 131112131335 its reverse (533131211131), we get a palindrome (664243342466).

The spelling of 131112131335 in words is "one hundred thirty-one billion, one hundred twelve million, one hundred thirty-one thousand, three hundred thirty-five".

Divisors: 1 5 89 445 294634003 1473170015 26222426267 131112131335