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13111220033 is a prime number
BaseRepresentation
bin11000011010111110…
…10101011101000001
31020211202001222122222
430031133111131001
5203322433020113
610005002540425
7642623350202
oct141537253501
936752058588
1013111220033
115618a3a73a
12265ab07715
13130c443482
148c543b5a9
1551b0c0e08
hex30d7d5741

13111220033 has 2 divisors, whose sum is σ = 13111220034. Its totient is φ = 13111220032.

The previous prime is 13111219991. The next prime is 13111220141. The reversal of 13111220033 is 33002211131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13110937009 + 283024 = 114503^2 + 532^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111220033 - 214 = 13111203649 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111219993 and 13111220020.

It is not a weakly prime, because it can be changed into another prime (13111223033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555610016 + 6555610017.

It is an arithmetic number, because the mean of its divisors is an integer number (6555610017).

Almost surely, 213111220033 is an apocalyptic number.

It is an amenable number.

13111220033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111220033 is an equidigital number, since it uses as much as digits as its factorization.

13111220033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108, while the sum is 17.

Adding to 13111220033 its reverse (33002211131), we get a palindrome (46113431164).

The spelling of 13111220033 in words is "thirteen billion, one hundred eleven million, two hundred twenty thousand, thirty-three".