13111220141 has 2 divisors, whose sum is σ = 13111220142. Its totient is φ = 13111220140.

The previous prime is 13111220033. The next prime is 13111220153. The reversal of 13111220141 is 14102211131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 12955220041 + 156000100 = 113821^2 + 12490^2 .

It is an emirp because it is prime and its reverse (14102211131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13111220141 - 2¹⁸ = 13110957997 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111220191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555610070 + 6555610071.

It is an arithmetic number, because the mean of its divisors is an integer number (6555610071).

Almost surely, 2^13111220141 is an apocalyptic number.

It is an amenable number.

13111220141 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111220141 is an equidigital number, since it uses as much as digits as its factorization.

13111220141 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 17.

Adding to 13111220141 its reverse (14102211131), we get a palindrome (27213431272).

The spelling of 13111220141 in words is "thirteen billion, one hundred eleven million, two hundred twenty thousand, one hundred forty-one".