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1311122431 is a prime number
BaseRepresentation
bin100111000100110…
…0010001111111111
310101101002220212001
41032021202033333
510141121404211
6334033523131
744330233243
oct11611421777
93341086761
101311122431
11613104763
123071134a7
1317b8306b8
14c61b8423
157a18aac1
hex4e2623ff

1311122431 has 2 divisors, whose sum is σ = 1311122432. Its totient is φ = 1311122430.

The previous prime is 1311122419. The next prime is 1311122443. The reversal of 1311122431 is 1342211131.

It is a balanced prime because it is at equal distance from previous prime (1311122419) and next prime (1311122443).

It is an emirp because it is prime and its reverse (1342211131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1311122431 - 29 = 1311121919 is a prime.

It is a super-2 number, since 2×13111224312 = 3438084058142699522, which contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311122399 and 1311122408.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1311120431) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655561215 + 655561216.

It is an arithmetic number, because the mean of its divisors is an integer number (655561216).

Almost surely, 21311122431 is an apocalyptic number.

1311122431 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311122431 is an equidigital number, since it uses as much as digits as its factorization.

1311122431 is an evil number, because the sum of its binary digits is even.

The product of its digits is 144, while the sum is 19.

The square root of 1311122431 is about 36209.4246156992. The cubic root of 1311122431 is about 1094.4965975584.

Adding to 1311122431 its reverse (1342211131), we get a palindrome (2653333562).

The spelling of 1311122431 in words is "one billion, three hundred eleven million, one hundred twenty-two thousand, four hundred thirty-one".