131112330034240 has 28 divisors (see below), whose sum is σ = 312211235894796. Its totient is φ = 52444932013568.

The previous prime is 131112330034237. The next prime is 131112330034247. The reversal of 131112330034240 is 42430033211131.

131112330034240 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 71691172780096 + 59421157254144 = 8467064^2 + 7708512^2 .

It is a junction number, because it is equal to n+sod(n) for n = 131112330034199 and 131112330034208.

It is not an unprimeable number, because it can be changed into a prime (131112330034247) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 204863015359 + ... + 204863015998.

It is an arithmetic number, because the mean of its divisors is an integer number (11150401281957).

Almost surely, 2^{131112330034240} is an apocalyptic number.

131112330034240 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131112330034240 is an abundant number, since it is smaller than the sum of its proper divisors (181098905860556).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131112330034240 is an equidigital number, since it uses as much as digits as its factorization.

131112330034240 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 409726031374 (or 409726031364 counting only the distinct ones).

The product of its (nonzero) digits is 5184, while the sum is 28.

Adding to 131112330034240 its reverse (42430033211131), we get a palindrome (173542363245371).

The spelling of 131112330034240 in words is "one hundred thirty-one trillion, one hundred twelve billion, three hundred thirty million, thirty-four thousand, two hundred forty".