Base | Representation |
---|---|
bin | 1011111011001011001001… |
… | …1001011100011101100100 |
3 | 1201102102101101101122210110 |
4 | 2332302302121130131210 |
5 | 3204303301144431040 |
6 | 43515114542053020 |
7 | 2522153403253122 |
oct | 276626231343544 |
9 | 51372341348713 |
10 | 13111233202020 |
11 | 41a5496373828 |
12 | 157906557a170 |
13 | 7414cb803055 |
14 | 334830cdc912 |
15 | 17b0beb77980 |
hex | becb265c764 |
13111233202020 has 48 divisors (see below), whose sum is σ = 36895932662400. Its totient is φ = 3478759358976.
The previous prime is 13111233202009. The next prime is 13111233202051. The reversal of 13111233202020 is 2020233211131.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 549034677 + ... + 549058556.
It is an arithmetic number, because the mean of its divisors is an integer number (768665263800).
Almost surely, 213111233202020 is an apocalyptic number.
13111233202020 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
13111233202020 is an abundant number, since it is smaller than the sum of its proper divisors (23784699460380).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111233202020 is a wasteful number, since it uses less digits than its factorization.
13111233202020 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1098093444 (or 1098093442 counting only the distinct ones).
The product of its (nonzero) digits is 432, while the sum is 21.
Adding to 13111233202020 its reverse (2020233211131), we get a palindrome (15131466413151).
The spelling of 13111233202020 in words is "thirteen trillion, one hundred eleven billion, two hundred thirty-three million, two hundred two thousand, twenty".
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