13111302300330 has 256 divisors, whose sum is σ = 36351420973056. Its totient is φ = 2997981020160.

The previous prime is 13111302300323. The next prime is 13111302300379. The reversal of 13111302300330 is 3300320311131.

It is a junction number, because it is equal to n+sod(n) for n = 13111302300297 and 13111302300306.

It is an unprimeable number.

It is a polite number, since it can be written in 127 ways as a sum of consecutive naturals, for example, 162467590 + ... + 162548270.

It is an arithmetic number, because the mean of its divisors is an integer number (141997738176).

Almost surely, 2^{13111302300330} is an apocalyptic number.

13111302300330 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13111302300330, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (18175710486528).

13111302300330 is an abundant number, since it is smaller than the sum of its proper divisors (23240118672726).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13111302300330 is a wasteful number, since it uses less digits than its factorization.

13111302300330 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 81041.

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 13111302300330 its reverse (3300320311131), we get a palindrome (16411622611461).

The spelling of 13111302300330 in words is "thirteen trillion, one hundred eleven billion, three hundred two million, three hundred thousand, three hundred thirty".