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131113203330000 = 2435437118120003
BaseRepresentation
bin11101110011111100101011…
…111010001110101111010000
3122012020022002120110201021210
4131303330223322032233100
5114141124320023030000
61142504324000420120
736421421255660463
oct3563745372165720
9565208076421253
10131113203330000
113885a8851904a1
121285674a617640
135820bca8b4058
142453cacddd2da
15102584e262350
hex773f2be8ebd0

131113203330000 has 200 divisors, whose sum is σ = 434690119360288. Its totient is φ = 34018560576000.

The previous prime is 131113203329993. The next prime is 131113203330089. The reversal of 131113203330000 is 33302311131.

It is a tau number, because it is divible by the number of its divisors (200).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 39 ways as a sum of consecutive naturals, for example, 57950002 + ... + 60170001.

Almost surely, 2131113203330000 is an apocalyptic number.

131113203330000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

131113203330000 is an abundant number, since it is smaller than the sum of its proper divisors (303576916030288).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131113203330000 is a wasteful number, since it uses less digits than its factorization.

131113203330000 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 118120071 (or 118120050 counting only the distinct ones).

The product of its (nonzero) digits is 486, while the sum is 21.

Adding to 131113203330000 its reverse (33302311131), we get a palindrome (131146505641131).

The spelling of 131113203330000 in words is "one hundred thirty-one trillion, one hundred thirteen billion, two hundred three million, three hundred thirty thousand".