Base | Representation |
---|---|
bin | 10011000101000101101… |
… | …000000110001100101111 |
3 | 11122100021010100210120222 |
4 | 103011011220012030233 |
5 | 132440200042224320 |
6 | 2442154250001555 |
7 | 163504050004421 |
oct | 23050550061457 |
9 | 4570233323528 |
10 | 1311133164335 |
11 | 466059543355 |
12 | 192133a162bb |
13 | 968407a7947 |
14 | 47660000811 |
15 | 2418b51a825 |
hex | 13145a0632f |
1311133164335 has 16 divisors (see below), whose sum is σ = 1701355280256. Its totient is φ = 966201758208.
The previous prime is 1311133164277. The next prime is 1311133164349. The reversal of 1311133164335 is 5334613311131.
It is a cyclic number.
It is not a de Polignac number, because 1311133164335 - 28 = 1311133164079 is a prime.
It is a super-2 number, since 2×13111331643352 (a number of 25 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 1311133164295 and 1311133164304.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 164092772 + ... + 164100761.
It is an arithmetic number, because the mean of its divisors is an integer number (106334705016).
Almost surely, 21311133164335 is an apocalyptic number.
1311133164335 is a deficient number, since it is larger than the sum of its proper divisors (390222115921).
1311133164335 is a wasteful number, since it uses less digits than its factorization.
1311133164335 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 328193602.
The product of its digits is 29160, while the sum is 35.
Adding to 1311133164335 its reverse (5334613311131), we get a palindrome (6645746475466).
The spelling of 1311133164335 in words is "one trillion, three hundred eleven billion, one hundred thirty-three million, one hundred sixty-four thousand, three hundred thirty-five".
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