13111332041030 has 64 divisors (see below), whose sum is σ = 23969550559680. Its totient is φ = 5163297484800.

The previous prime is 13111332040987. The next prime is 13111332041033. The reversal of 13111332041030 is 3014023311131.

It is a junction number, because it is equal to n+sod(n) for n = 13111332040987 and 13111332041005.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111332041033) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 84219422 + ... + 84374958.

It is an arithmetic number, because the mean of its divisors is an integer number (374524227495).

Almost surely, 2^{13111332041030} is an apocalyptic number.

13111332041030 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

13111332041030 is a deficient number, since it is larger than the sum of its proper divisors (10858218518650).

13111332041030 is a wasteful number, since it uses less digits than its factorization.

13111332041030 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 156185.

The product of its (nonzero) digits is 648, while the sum is 23.

Adding to 13111332041030 its reverse (3014023311131), we get a palindrome (16125355352161).

The spelling of 13111332041030 in words is "thirteen trillion, one hundred eleven billion, three hundred thirty-two million, forty-one thousand, thirty".