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13111340023 = 433242312497
BaseRepresentation
bin11000011010111111…
…10010101111110111
31020211202022002021001
430031133302233313
5203323000340043
610005005304131
7642624360055
oct141537625767
936752262231
1013111340023
115619011901
12265ab65047
13130c485c82
148c546d1d5
1551b0e674d
hex30d7f2bf7

13111340023 has 8 divisors (see below), whose sum is σ = 13148095968. Its totient is φ = 13074614784.

The previous prime is 13111340009. The next prime is 13111340059. The reversal of 13111340023 is 32004311131.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13111340023 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13111340063) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1042911 + ... + 1055407.

It is an arithmetic number, because the mean of its divisors is an integer number (1643511996).

Almost surely, 213111340023 is an apocalyptic number.

13111340023 is a deficient number, since it is larger than the sum of its proper divisors (36755945).

13111340023 is a wasteful number, since it uses less digits than its factorization.

13111340023 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 15353.

The product of its (nonzero) digits is 216, while the sum is 19.

Adding to 13111340023 its reverse (32004311131), we get a palindrome (45115651154).

The spelling of 13111340023 in words is "thirteen billion, one hundred eleven million, three hundred forty thousand, twenty-three".

Divisors: 1 433 2423 12497 1049159 5411201 30280231 13111340023