Base | Representation |
---|---|
bin | 1011111011001011110001… |
… | …0111110000000110110000 |
3 | 1201102102211001020211010002 |
4 | 2332302330113300012300 |
5 | 3204304122013432402 |
6 | 43515143320325132 |
7 | 2522160504443615 |
oct | 276627427600660 |
9 | 51372731224102 |
10 | 13111400530352 |
11 | 41a5571871003 |
12 | 15790b16137a8 |
13 | 74152738b2b7 |
14 | 33484921850c |
15 | 17b0ce6cb602 |
hex | becbc5f01b0 |
13111400530352 has 40 divisors (see below), whose sum is σ = 27224259413856. Its totient is φ = 6101192249856.
The previous prime is 13111400530273. The next prime is 13111400530363. The reversal of 13111400530352 is 25303500411131.
It is a super-3 number, since 3×131114005303523 (a number of 40 digits) contains 333 as substring.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 481456733 + ... + 481483964.
Almost surely, 213111400530352 is an apocalyptic number.
It is an amenable number.
13111400530352 is an abundant number, since it is smaller than the sum of its proper divisors (14112858883504).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
13111400530352 is a wasteful number, since it uses less digits than its factorization.
13111400530352 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 962940765 (or 962940759 counting only the distinct ones).
The product of its (nonzero) digits is 5400, while the sum is 29.
Adding to 13111400530352 its reverse (25303500411131), we get a palindrome (38414900941483).
The spelling of 13111400530352 in words is "thirteen trillion, one hundred eleven billion, four hundred million, five hundred thirty thousand, three hundred fifty-two".
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