Base | Representation |
---|---|
bin | 1011111011001011110010… |
… | …0111000100001111111111 |
3 | 1201102102211022210210012121 |
4 | 2332302330213010033333 |
5 | 3204304124030420043 |
6 | 43515143542343411 |
7 | 2522160553534321 |
oct | 276627447041777 |
9 | 51372738723177 |
10 | 13111404545023 |
11 | 41a5574063314 |
12 | 15790b2a2ab67 |
13 | 741528165745 |
14 | 334849981611 |
15 | 17b0cec20ded |
hex | becbc9c43ff |
13111404545023 has 2 divisors, whose sum is σ = 13111404545024. Its totient is φ = 13111404545022.
The previous prime is 13111404545009. The next prime is 13111404545033. The reversal of 13111404545023 is 32054540411131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13111404545023 - 217 = 13111404413951 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13111404545023.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13111404545033) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555702272511 + 6555702272512.
It is an arithmetic number, because the mean of its divisors is an integer number (6555702272512).
Almost surely, 213111404545023 is an apocalyptic number.
13111404545023 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111404545023 is an equidigital number, since it uses as much as digits as its factorization.
13111404545023 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 28800, while the sum is 34.
Adding to 13111404545023 its reverse (32054540411131), we get a palindrome (45165944956154).
The spelling of 13111404545023 in words is "thirteen trillion, one hundred eleven billion, four hundred four million, five hundred forty-five thousand, twenty-three".
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