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13111404545033 is a prime number
BaseRepresentation
bin1011111011001011110010…
…0111000100010000001001
31201102102211022210210012222
42332302330213010100021
53204304124030420113
643515143542343425
72522160553534334
oct276627447042011
951372738723188
1013111404545033
1141a5574063323
1215790b2a2ab75
13741528165752
1433484998161b
1517b0cec20e08
hexbecbc9c4409

13111404545033 has 2 divisors, whose sum is σ = 13111404545034. Its totient is φ = 13111404545032.

The previous prime is 13111404545023. The next prime is 13111404545051. The reversal of 13111404545033 is 33054540411131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11541728825344 + 1569675719689 = 3397312^2 + 1252867^2 .

It is a cyclic number.

It is not a de Polignac number, because 13111404545033 - 26 = 13111404544969 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 13111404544984 and 13111404545002.

It is not a weakly prime, because it can be changed into another prime (13111404545023) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555702272516 + 6555702272517.

It is an arithmetic number, because the mean of its divisors is an integer number (6555702272517).

Almost surely, 213111404545033 is an apocalyptic number.

It is an amenable number.

13111404545033 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111404545033 is an equidigital number, since it uses as much as digits as its factorization.

13111404545033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 43200, while the sum is 35.

Adding to 13111404545033 its reverse (33054540411131), we get a palindrome (46165944956164).

The spelling of 13111404545033 in words is "thirteen trillion, one hundred eleven billion, four hundred four million, five hundred forty-five thousand, thirty-three".