Base | Representation |
---|---|
bin | 11000011011000000… |
… | …01001011111010011 |
3 | 1020211202110211000222 |
4 | 30031200021133103 |
5 | 203323011330141 |
6 | 10005011303255 |
7 | 642625225454 |
oct | 141540113723 |
9 | 36752424028 |
10 | 13111433171 |
11 | 5619075891 |
12 | 265abaab2b |
13 | 130c4b94a5 |
14 | 8c549512b |
15 | 51b11414b |
hex | 30d8097d3 |
13111433171 has 2 divisors, whose sum is σ = 13111433172. Its totient is φ = 13111433170.
The previous prime is 13111433119. The next prime is 13111433197. The reversal of 13111433171 is 17133411131.
It is an a-pointer prime, because the next prime (13111433197) can be obtained adding 13111433171 to its sum of digits (26).
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-13111433171 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 13111433171.
It is not a weakly prime, because it can be changed into another prime (13111433371) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555716585 + 6555716586.
It is an arithmetic number, because the mean of its divisors is an integer number (6555716586).
Almost surely, 213111433171 is an apocalyptic number.
13111433171 is a deficient number, since it is larger than the sum of its proper divisors (1).
13111433171 is an equidigital number, since it uses as much as digits as its factorization.
13111433171 is an evil number, because the sum of its binary digits is even.
The product of its digits is 756, while the sum is 26.
The spelling of 13111433171 in words is "thirteen billion, one hundred eleven million, four hundred thirty-three thousand, one hundred seventy-one".
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