13111433119 has 2 divisors, whose sum is σ = 13111433120. Its totient is φ = 13111433118.

The previous prime is 13111433063. The next prime is 13111433171. The reversal of 13111433119 is 91133411131.

It is a happy number.

13111433119 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13111433119 - 2¹¹ = 13111431071 is a prime.

It is a super-2 number, since 2×13111433119² (a number of 21 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13111433519) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555716559 + 6555716560.

It is an arithmetic number, because the mean of its divisors is an integer number (6555716560).

Almost surely, 2^13111433119 is an apocalyptic number.

13111433119 is a deficient number, since it is larger than the sum of its proper divisors (1).

13111433119 is an equidigital number, since it uses as much as digits as its factorization.

13111433119 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 972, while the sum is 28.

The spelling of 13111433119 in words is "thirteen billion, one hundred eleven million, four hundred thirty-three thousand, one hundred nineteen".