Base | Representation |
---|---|
bin | 11101110011111110101001… |
… | …101110111101100011100010 |
3 | 122012020111112200122100221022 |
4 | 131303332221232331203202 |
5 | 114141143130430232000 |
6 | 1142505313250125442 |
7 | 36421524500655332 |
oct | 3563765156754342 |
9 | 565214480570838 |
10 | 131115314305250 |
11 | 38860768835440 |
12 | 12857039580882 |
13 | 5821176045632 |
14 | 245402d5050c2 |
15 | 1025924746585 |
hex | 773fa9bbd8e2 |
131115314305250 has 128 divisors (see below), whose sum is σ = 275335072556544. Its totient is φ = 46338535680000.
The previous prime is 131115314305177. The next prime is 131115314305361. The reversal of 131115314305250 is 52503413511131.
It is a self number, because there is not a number n which added to its sum of digits gives 131115314305250.
It is an unprimeable number.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 27442442 + ... + 31864058.
It is an arithmetic number, because the mean of its divisors is an integer number (2151055254348).
Almost surely, 2131115314305250 is an apocalyptic number.
131115314305250 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131115314305250 is an abundant number, since it is smaller than the sum of its proper divisors (144219758251294).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131115314305250 is a wasteful number, since it uses less digits than its factorization.
131115314305250 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4421949 (or 4421939 counting only the distinct ones).
The product of its (nonzero) digits is 27000, while the sum is 35.
Adding to 131115314305250 its reverse (52503413511131), we get a palindrome (183618727816381).
The spelling of 131115314305250 in words is "one hundred thirty-one trillion, one hundred fifteen billion, three hundred fourteen million, three hundred five thousand, two hundred fifty".
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