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1311161190551 = 2335627301247
BaseRepresentation
bin10011000101000111010…
…011000000100010010111
311122100100002002200022222
4103011013103000202113
5132440224231044201
62442201130412555
7163504540142462
oct23050723004227
94570302080288
101311161190551
11466073345913
1219214129115b
139684653b3c4
1447663a182d9
152418dc0491b
hex131474c0897

1311161190551 has 4 divisors (see below), whose sum is σ = 1316788492032. Its totient is φ = 1305533889072.

The previous prime is 1311161190539. The next prime is 1311161190571. The reversal of 1311161190551 is 1550911611131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1311161190551 - 230 = 1310087448727 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311161190571) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2813650391 + ... + 2813650856.

It is an arithmetic number, because the mean of its divisors is an integer number (329197123008).

Almost surely, 21311161190551 is an apocalyptic number.

1311161190551 is a deficient number, since it is larger than the sum of its proper divisors (5627301481).

1311161190551 is an equidigital number, since it uses as much as digits as its factorization.

1311161190551 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 5627301480.

The product of its (nonzero) digits is 4050, while the sum is 35.

The spelling of 1311161190551 in words is "one trillion, three hundred eleven billion, one hundred sixty-one million, one hundred ninety thousand, five hundred fifty-one".

Divisors: 1 233 5627301247 1311161190551