Base | Representation |
---|---|
bin | 111101000011101011… |
… | …1001110110011101011 |
3 | 110112102222110211001122 |
4 | 1322013113032303223 |
5 | 4122013212024003 |
6 | 140122525205455 |
7 | 12321163614461 |
oct | 1720727166353 |
9 | 415388424048 |
10 | 131120033003 |
11 | 50675927543 |
12 | 214b3a0088b |
13 | c497c4a95b |
14 | 64bc140831 |
15 | 3626355238 |
hex | 1e875ceceb |
131120033003 has 4 divisors (see below), whose sum is σ = 131124925800. Its totient is φ = 131115140208.
The previous prime is 131120032997. The next prime is 131120033089. The reversal of 131120033003 is 300330021131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 131120033003 - 220 = 131118984427 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (131120033203) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2405978 + ... + 2459871.
It is an arithmetic number, because the mean of its divisors is an integer number (32781231450).
Almost surely, 2131120033003 is an apocalyptic number.
131120033003 is a deficient number, since it is larger than the sum of its proper divisors (4892797).
131120033003 is an equidigital number, since it uses as much as digits as its factorization.
131120033003 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 4892796.
The product of its (nonzero) digits is 162, while the sum is 17.
Adding to 131120033003 its reverse (300330021131), we get a palindrome (431450054134).
The spelling of 131120033003 in words is "one hundred thirty-one billion, one hundred twenty million, thirty-three thousand, three".
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