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13112011292909 is a prime number
BaseRepresentation
bin1011111011001110000011…
…0001101000000011101101
31201102111101121111202211112
42332303200301220003231
53204311344342333114
643515324055201405
72522211602026514
oct276634061500355
951374347452745
1013112011292909
1141a58555aaa51
121579242076265
137415c3a84869
143348a63a367b
1517b11812313e
hexbece0c680ed

13112011292909 has 2 divisors, whose sum is σ = 13112011292910. Its totient is φ = 13112011292908.

The previous prime is 13112011292881. The next prime is 13112011292911. The reversal of 13112011292909 is 90929211021131.

13112011292909 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8645234717284 + 4466776575625 = 2940278^2 + 2113475^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112011292909 is a prime.

Together with 13112011292911, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112011292959) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556005646454 + 6556005646455.

It is an arithmetic number, because the mean of its divisors is an integer number (6556005646455).

Almost surely, 213112011292909 is an apocalyptic number.

It is an amenable number.

13112011292909 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112011292909 is an equidigital number, since it uses as much as digits as its factorization.

13112011292909 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 17496, while the sum is 41.

The spelling of 13112011292909 in words is "thirteen trillion, one hundred twelve billion, eleven million, two hundred ninety-two thousand, nine hundred nine".