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13112011301122 = 26556005650561
BaseRepresentation
bin1011111011001110000011…
…0001101010000100000010
31201102111101121112012002201
42332303200301222010002
53204311344343113442
643515324055303414
72522211602062456
oct276634061520402
951374347465081
1013112011301122
1141a5855606138
12157924207ab6a
137415c3a88516
143348a63a6666
1517b1181257b7
hexbece0c6a102

13112011301122 has 4 divisors (see below), whose sum is σ = 19668016951686. Its totient is φ = 6556005650560.

The previous prime is 13112011301111. The next prime is 13112011301131. The reversal of 13112011301122 is 22110311021131.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 12402237065761 + 709774235361 = 3521681^2 + 842481^2 .

It is a self number, because there is not a number n which added to its sum of digits gives 13112011301122.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 3278002825279 + ... + 3278002825282.

Almost surely, 213112011301122 is an apocalyptic number.

13112011301122 is a deficient number, since it is larger than the sum of its proper divisors (6556005650564).

13112011301122 is an equidigital number, since it uses as much as digits as its factorization.

13112011301122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 6556005650563.

The product of its (nonzero) digits is 72, while the sum is 19.

Adding to 13112011301122 its reverse (22110311021131), we get a palindrome (35222322322253).

The spelling of 13112011301122 in words is "thirteen trillion, one hundred twelve billion, eleven million, three hundred one thousand, one hundred twenty-two".

Divisors: 1 2 6556005650561 13112011301122