Base | Representation |
---|---|
bin | 1011111011001110000011… |
… | …0101011110101111001111 |
3 | 1201102111101200102002211211 |
4 | 2332303200311132233033 |
5 | 3204311400122201221 |
6 | 43515324132555251 |
7 | 2522211613435345 |
oct | 276634065365717 |
9 | 51374350362754 |
10 | 13112012303311 |
11 | 41a5856130099 |
12 | 1579242482b27 |
13 | 7415c404972c |
14 | 3348a6587995 |
15 | 17b1182726e1 |
hex | bece0d5ebcf |
13112012303311 has 2 divisors, whose sum is σ = 13112012303312. Its totient is φ = 13112012303310.
The previous prime is 13112012303287. The next prime is 13112012303339. The reversal of 13112012303311 is 11330321021131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13112012303311 - 29 = 13112012302799 is a prime.
It is a super-3 number, since 3×131120123033113 (a number of 40 digits) contains 333 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112012303711) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556006151655 + 6556006151656.
It is an arithmetic number, because the mean of its divisors is an integer number (6556006151656).
Almost surely, 213112012303311 is an apocalyptic number.
13112012303311 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112012303311 is an equidigital number, since it uses as much as digits as its factorization.
13112012303311 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 22.
Adding to 13112012303311 its reverse (11330321021131), we get a palindrome (24442333324442).
The spelling of 13112012303311 in words is "thirteen trillion, one hundred twelve billion, twelve million, three hundred three thousand, three hundred eleven".
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