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13112012437 is a prime number
BaseRepresentation
bin11000011011000100…
…10110111010010101
31020211210120020122021
430031202112322111
5203323133344222
610005031533141
7642633160336
oct141542267225
936753506567
1013112012437
115619431017
12265b22a1b1
13130c660054
148c55a628d
1551b1caac7
hex30d896e95

13112012437 has 2 divisors, whose sum is σ = 13112012438. Its totient is φ = 13112012436.

The previous prime is 13112012377. The next prime is 13112012449. The reversal of 13112012437 is 73421021131.

13112012437 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10950785316 + 2161227121 = 104646^2 + 46489^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-13112012437 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112010437) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556006218 + 6556006219.

It is an arithmetic number, because the mean of its divisors is an integer number (6556006219).

Almost surely, 213112012437 is an apocalyptic number.

It is an amenable number.

13112012437 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112012437 is an equidigital number, since it uses as much as digits as its factorization.

13112012437 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 1008, while the sum is 25.

Adding to 13112012437 its reverse (73421021131), we get a palindrome (86533033568).

The spelling of 13112012437 in words is "thirteen billion, one hundred twelve million, twelve thousand, four hundred thirty-seven".