Base | Representation |
---|---|
bin | 10011000101001001101… |
… | …100100001011000110101 |
3 | 11122100102212211012210021 |
4 | 103011021230201120311 |
5 | 132440320031330031 |
6 | 2442205125125141 |
7 | 163505536201015 |
oct | 23051154413065 |
9 | 4570385735707 |
10 | 1311201433141 |
11 | 466094031756 |
12 | 1921528597b1 |
13 | 9685198b4a2 |
14 | 476690d1c45 |
15 | 24192503511 |
hex | 13149b21635 |
1311201433141 has 2 divisors, whose sum is σ = 1311201433142. Its totient is φ = 1311201433140.
The previous prime is 1311201433123. The next prime is 1311201433159. The reversal of 1311201433141 is 1413341021131.
It is a balanced prime because it is at equal distance from previous prime (1311201433123) and next prime (1311201433159).
It can be written as a sum of positive squares in only one way, i.e., 1194548446116 + 116652987025 = 1092954^2 + 341545^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311201433141 - 27 = 1311201433013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311201433111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655600716570 + 655600716571.
It is an arithmetic number, because the mean of its divisors is an integer number (655600716571).
Almost surely, 21311201433141 is an apocalyptic number.
It is an amenable number.
1311201433141 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311201433141 is an equidigital number, since it uses as much as digits as its factorization.
1311201433141 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 864, while the sum is 25.
Adding to 1311201433141 its reverse (1413341021131), we get a palindrome (2724542454272).
The spelling of 1311201433141 in words is "one trillion, three hundred eleven billion, two hundred one million, four hundred thirty-three thousand, one hundred forty-one".
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