Base | Representation |
---|---|
bin | 1011111011001110000101… |
… | …1111100001101101101101 |
3 | 1201102111102110011002111212 |
4 | 2332303201133201231231 |
5 | 3204311410432404144 |
6 | 43515325205124205 |
7 | 2522212106223221 |
oct | 276634137415555 |
9 | 51374373132455 |
10 | 13112023325549 |
11 | 41a5861379285 |
12 | 15792460b9665 |
13 | 7415c6408675 |
14 | 3348a7c16781 |
15 | 17b1191ed49e |
hex | bece17e1b6d |
13112023325549 has 2 divisors, whose sum is σ = 13112023325550. Its totient is φ = 13112023325548.
The previous prime is 13112023325543. The next prime is 13112023325581. The reversal of 13112023325549 is 94552332021131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 11612978159524 + 1499045166025 = 3407782^2 + 1224355^2 .
It is a cyclic number.
It is not a de Polignac number, because 13112023325549 - 216 = 13112023260013 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112023325543) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556011662774 + 6556011662775.
It is an arithmetic number, because the mean of its divisors is an integer number (6556011662775).
Almost surely, 213112023325549 is an apocalyptic number.
It is an amenable number.
13112023325549 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112023325549 is an equidigital number, since it uses as much as digits as its factorization.
13112023325549 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 194400, while the sum is 41.
The spelling of 13112023325549 in words is "thirteen trillion, one hundred twelve billion, twenty-three million, three hundred twenty-five thousand, five hundred forty-nine".
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