13112023325581 has 2 divisors, whose sum is σ = 13112023325582. Its totient is φ = 13112023325580.

The previous prime is 13112023325549. The next prime is 13112023325587. The reversal of 13112023325581 is 18552332021131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 11294741385225 + 1817281940356 = 3360765^2 + 1348066^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112023325581 - 2⁵ = 13112023325549 is a prime.

It is a super-3 number, since 3×13112023325581³ (a number of 40 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a self number, because there is not a number n which added to its sum of digits gives 13112023325581.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13112023325587) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556011662790 + 6556011662791.

It is an arithmetic number, because the mean of its divisors is an integer number (6556011662791).

Almost surely, 2^{13112023325581} is an apocalyptic number.

It is an amenable number.

13112023325581 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112023325581 is an equidigital number, since it uses as much as digits as its factorization.

13112023325581 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 43200, while the sum is 37.

The spelling of 13112023325581 in words is "thirteen trillion, one hundred twelve billion, twenty-three million, three hundred twenty-five thousand, five hundred eighty-one".