Base | Representation |
---|---|
bin | 11101110100000011010011… |
… | …100001101011000100001011 |
3 | 122012020222102212201220102012 |
4 | 131310003103201223010023 |
5 | 114141233343432311021 |
6 | 1142511501122330135 |
7 | 36422062345231505 |
oct | 3564032341530413 |
9 | 565228385656365 |
10 | 131120310432011 |
11 | 388628a1a3741a |
12 | 12857bb27b994b |
13 | 5821791149264 |
14 | 2454384c78d75 |
15 | 1025b1818535b |
hex | 7740d386b10b |
131120310432011 has 2 divisors, whose sum is σ = 131120310432012. Its totient is φ = 131120310432010.
The previous prime is 131120310431951. The next prime is 131120310432047. The reversal of 131120310432011 is 110234013021131.
It is a strong prime.
It is an emirp because it is prime and its reverse (110234013021131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131120310432011 - 242 = 126722263920907 is a prime.
It is not a weakly prime, because it can be changed into another prime (131120310432311) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560155216005 + 65560155216006.
It is an arithmetic number, because the mean of its divisors is an integer number (65560155216006).
Almost surely, 2131120310432011 is an apocalyptic number.
131120310432011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131120310432011 is an equidigital number, since it uses as much as digits as its factorization.
131120310432011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 432, while the sum is 23.
Adding to 131120310432011 its reverse (110234013021131), we get a palindrome (241354323453142).
The spelling of 131120310432011 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred ten million, four hundred thirty-two thousand, eleven".
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