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131120310432047 is a prime number
BaseRepresentation
bin11101110100000011010011…
…100001101011000100101111
3122012020222102212201220110112
4131310003103201223010233
5114141233343432311142
61142511501122330235
736422062345231556
oct3564032341530457
9565228385656415
10131120310432047
11388628a1a37452
1212857bb27b997b
135821791149291
142454384c78d9d
151025b18185382
hex7740d386b12f

131120310432047 has 2 divisors, whose sum is σ = 131120310432048. Its totient is φ = 131120310432046.

The previous prime is 131120310432011. The next prime is 131120310432079. The reversal of 131120310432047 is 740234013021131.

It is an a-pointer prime, because the next prime (131120310432079) can be obtained adding 131120310432047 to its sum of digits (32).

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 131120310432047 - 28 = 131120310431791 is a prime.

It is a super-2 number, since 2×1311203104320472 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131120310432347) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560155216023 + 65560155216024.

It is an arithmetic number, because the mean of its divisors is an integer number (65560155216024).

Almost surely, 2131120310432047 is an apocalyptic number.

131120310432047 is a deficient number, since it is larger than the sum of its proper divisors (1).

131120310432047 is an equidigital number, since it uses as much as digits as its factorization.

131120310432047 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12096, while the sum is 32.

Adding to 131120310432047 its reverse (740234013021131), we get a palindrome (871354323453178).

The spelling of 131120310432047 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred ten million, four hundred thirty-two thousand, forty-seven".