131120310550500 has 288 divisors, whose sum is σ = 424124949201408. Its totient is φ = 34085116800000.

The previous prime is 131120310550469. The next prime is 131120310550597. The reversal of 131120310550500 is 5055013021131.

131120310550500 is a `hidden beast` number, since 1 + 3 + 1 + 1 + 2 + 0 + 3 + 105 + 50 + 500 = 666.

It is a super-3 number, since 3×131120310550500³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is an unprimeable number.

It is a polite number, since it can be written in 95 ways as a sum of consecutive naturals, for example, 51851532 + ... + 54321468.

It is an arithmetic number, because the mean of its divisors is an integer number (1472656073616).

Almost surely, 2^{131120310550500} is an apocalyptic number.

131120310550500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131120310550500, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (212062474600704).

131120310550500 is an abundant number, since it is smaller than the sum of its proper divisors (293004638650908).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131120310550500 is a wasteful number, since it uses less digits than its factorization.

131120310550500 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 2470260 (or 2470245 counting only the distinct ones).

The product of its (nonzero) digits is 2250, while the sum is 27.

Adding to 131120310550500 its reverse (5055013021131), we get a palindrome (136175323571631).

The spelling of 131120310550500 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred ten million, five hundred fifty thousand, five hundred".