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13112031235049 is a prime number
BaseRepresentation
bin1011111011001110000111…
…1101101100101111101001
31201102111110000000221022022
42332303201331230233221
53204311414444010144
643515330050434225
72522212233365045
oct276634175545751
951374400027268
1013112031235049
1141a586589085a
121579248892975
137415c7c47846
143348a8cb5025
1517b119c61cee
hexbece1f6cbe9

13112031235049 has 2 divisors, whose sum is σ = 13112031235050. Its totient is φ = 13112031235048.

The previous prime is 13112031234961. The next prime is 13112031235063. The reversal of 13112031235049 is 94053213021131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 9059540148649 + 4052491086400 = 3009907^2 + 2013080^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112031235049 - 224 = 13112014457833 is a prime.

It is not a weakly prime, because it can be changed into another prime (13112031235249) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556015617524 + 6556015617525.

It is an arithmetic number, because the mean of its divisors is an integer number (6556015617525).

Almost surely, 213112031235049 is an apocalyptic number.

It is an amenable number.

13112031235049 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112031235049 is an equidigital number, since it uses as much as digits as its factorization.

13112031235049 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 19440, while the sum is 35.

The spelling of 13112031235049 in words is "thirteen trillion, one hundred twelve billion, thirty-one million, two hundred thirty-five thousand, forty-nine".