13112031235050 has 144 divisors (see below), whose sum is σ = 38446677835488. Its totient is φ = 3177308956800.

The previous prime is 13112031235049. The next prime is 13112031235063. The reversal of 13112031235050 is 5053213021131.

13112031235050 is a `hidden beast` number, since 1 + 3 + 1 + 120 + 31 + 2 + 3 + 505 + 0 = 666.

It is an unprimeable number.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 10980649 + ... + 12116051.

It is an arithmetic number, because the mean of its divisors is an integer number (266990818302).

Almost surely, 2^{13112031235050} is an apocalyptic number.

13112031235050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13112031235050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (19223338917744).

13112031235050 is an abundant number, since it is smaller than the sum of its proper divisors (25334646600438).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13112031235050 is a wasteful number, since it uses less digits than its factorization.

13112031235050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1137765 (or 1137757 counting only the distinct ones).

The product of its (nonzero) digits is 2700, while the sum is 27.

Adding to 13112031235050 its reverse (5053213021131), we get a palindrome (18165244256181).

The spelling of 13112031235050 in words is "thirteen trillion, one hundred twelve billion, thirty-one million, two hundred thirty-five thousand, fifty".