Base | Representation |
---|---|
bin | 1011111011001110000111… |
… | …1101101100101111110111 |
3 | 1201102111110000000221022211 |
4 | 2332303201331230233313 |
5 | 3204311414444010223 |
6 | 43515330050434251 |
7 | 2522212233365065 |
oct | 276634175545767 |
9 | 51374400027284 |
10 | 13112031235063 |
11 | 41a5865890872 |
12 | 1579248892987 |
13 | 7415c7c47857 |
14 | 3348a8cb5035 |
15 | 17b119c61d0d |
hex | bece1f6cbf7 |
13112031235063 has 2 divisors, whose sum is σ = 13112031235064. Its totient is φ = 13112031235062.
The previous prime is 13112031235049. The next prime is 13112031235073. The reversal of 13112031235063 is 36053213021131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13112031235063 - 217 = 13112031103991 is a prime.
It is a super-2 number, since 2×131120312350632 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13112031235073) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556015617531 + 6556015617532.
It is an arithmetic number, because the mean of its divisors is an integer number (6556015617532).
Almost surely, 213112031235063 is an apocalyptic number.
13112031235063 is a deficient number, since it is larger than the sum of its proper divisors (1).
13112031235063 is an equidigital number, since it uses as much as digits as its factorization.
13112031235063 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 9720, while the sum is 31.
Adding to 13112031235063 its reverse (36053213021131), we get a palindrome (49165244256194).
The spelling of 13112031235063 in words is "thirteen trillion, one hundred twelve billion, thirty-one million, two hundred thirty-five thousand, sixty-three".
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