Base | Representation |
---|---|
bin | 11101110100000011010011… |
… | …101001000000101001010010 |
3 | 122012020222110000100121211012 |
4 | 131310003103221000221102 |
5 | 114141233344430333120 |
6 | 1142511501231450522 |
7 | 36422062400462210 |
oct | 3564032351005122 |
9 | 565228400317735 |
10 | 131120312355410 |
11 | 388628a3030504 |
12 | 12857bb3386a42 |
13 | 5821791670871 |
14 | 2454385219cb0 |
15 | 1025b184151c5 |
hex | 7740d3a40a52 |
131120312355410 has 32 divisors (see below), whose sum is σ = 272403839884032. Its totient is φ = 44510431348800.
The previous prime is 131120312355367. The next prime is 131120312355421. The reversal of 131120312355410 is 14553213021131.
131120312355410 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is an unprimeable number.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 9272999462 + ... + 9273013601.
It is an arithmetic number, because the mean of its divisors is an integer number (8512619996376).
Almost surely, 2131120312355410 is an apocalyptic number.
131120312355410 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131120312355410 is an abundant number, since it is smaller than the sum of its proper divisors (141283527528622).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131120312355410 is a wasteful number, since it uses less digits than its factorization.
131120312355410 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 18546013178.
The product of its (nonzero) digits is 10800, while the sum is 32.
Adding to 131120312355410 its reverse (14553213021131), we get a palindrome (145673525376541).
The spelling of 131120312355410 in words is "one hundred thirty-one trillion, one hundred twenty billion, three hundred twelve million, three hundred fifty-five thousand, four hundred ten".
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