Base | Representation |
---|---|
bin | 11101110100000011111100… |
… | …101001000011010001010101 |
3 | 122012021001012221201101010201 |
4 | 131310003330221003101111 |
5 | 114141241302024411041 |
6 | 1142512053403220501 |
7 | 36422115422361322 |
oct | 3564037451032125 |
9 | 565231187641121 |
10 | 131121000232021 |
11 | 3886311634a378 |
12 | 12858165817731 |
13 | 5821871026a47 |
14 | 245440c719b49 |
15 | 1025b589e0631 |
hex | 7740fca43455 |
131121000232021 has 2 divisors, whose sum is σ = 131121000232022. Its totient is φ = 131121000232020.
The previous prime is 131121000231941. The next prime is 131121000232063. The reversal of 131121000232021 is 120232000121131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 92428246109521 + 38692754122500 = 9613961^2 + 6220350^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131121000232021 is a prime.
It is a super-3 number, since 3×1311210002320213 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a self number, because there is not a number n which added to its sum of digits gives 131121000232021.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131121000235021) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65560500116010 + 65560500116011.
It is an arithmetic number, because the mean of its divisors is an integer number (65560500116011).
Almost surely, 2131121000232021 is an apocalyptic number.
It is an amenable number.
131121000232021 is a deficient number, since it is larger than the sum of its proper divisors (1).
131121000232021 is an equidigital number, since it uses as much as digits as its factorization.
131121000232021 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 131121000232021 its reverse (120232000121131), we get a palindrome (251353000353152).
The spelling of 131121000232021 in words is "one hundred thirty-one trillion, one hundred twenty-one billion, two hundred thirty-two thousand, twenty-one".
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