Base | Representation |
---|---|
bin | 111101000011101101… |
… | …1000000011001000111 |
3 | 110112110001100002102222 |
4 | 1322013123000121013 |
5 | 4122013440210120 |
6 | 140123002322555 |
7 | 12321205205426 |
oct | 1720733003107 |
9 | 415401302388 |
10 | 131121022535 |
11 | 50676442a38 |
12 | 214b41b945b |
13 | c498206189 |
14 | 64bc31b2bd |
15 | 362649d525 |
hex | 1e876c0647 |
131121022535 has 4 divisors (see below), whose sum is σ = 157345227048. Its totient is φ = 104896818024.
The previous prime is 131121022507. The next prime is 131121022537. The reversal of 131121022535 is 535220121131.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 535220121131 = 2203 ⋅242950577.
It is a cyclic number.
It is not a de Polignac number, because 131121022535 - 210 = 131121021511 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131121022537) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 13112102249 + ... + 13112102258.
It is an arithmetic number, because the mean of its divisors is an integer number (39336306762).
Almost surely, 2131121022535 is an apocalyptic number.
131121022535 is a deficient number, since it is larger than the sum of its proper divisors (26224204513).
131121022535 is an equidigital number, since it uses as much as digits as its factorization.
131121022535 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 26224204512.
The product of its (nonzero) digits is 1800, while the sum is 26.
Adding to 131121022535 its reverse (535220121131), we get a palindrome (666341143666).
The spelling of 131121022535 in words is "one hundred thirty-one billion, one hundred twenty-one million, twenty-two thousand, five hundred thirty-five".
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