1311211102013 has 4 divisors (see below), whose sum is σ = 1353508234368. Its totient is φ = 1268913969660.

The previous prime is 1311211102009. The next prime is 1311211102021. The reversal of 1311211102013 is 3102011121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311211102013 - 2² = 1311211102009 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1311211101982 and 1311211102000.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311211102913) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 21148566131 + ... + 21148566192.

It is an arithmetic number, because the mean of its divisors is an integer number (338377058592).

Almost surely, 2^{1311211102013} is an apocalyptic number.

It is an amenable number.

1311211102013 is a deficient number, since it is larger than the sum of its proper divisors (42297132355).

1311211102013 is an equidigital number, since it uses as much as digits as its factorization.

1311211102013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 42297132354.

The product of its (nonzero) digits is 36, while the sum is 17.

Adding to 1311211102013 its reverse (3102011121131), we get a palindrome (4413222223144).

The spelling of 1311211102013 in words is "one trillion, three hundred eleven billion, two hundred eleven million, one hundred two thousand, thirteen".