Base | Representation |
---|---|
bin | 10011000101001010010… |
… | …101010010011111010111 |
3 | 11122100110121221011102201 |
4 | 103011022111102133113 |
5 | 132440330300320043 |
6 | 2442210150145331 |
7 | 163506026061061 |
oct | 23051225223727 |
9 | 4570417834381 |
10 | 1311212120023 |
11 | 46609a070993 |
12 | 192156352247 |
13 | 96853c608a0 |
14 | 4766a6b4731 |
15 | 24193414c4d |
hex | 1314a5527d7 |
1311212120023 has 4 divisors (see below), whose sum is σ = 1412074590808. Its totient is φ = 1210349649240.
The previous prime is 1311212120021. The next prime is 1311212120083. The reversal of 1311212120023 is 3200212121131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311212120023 - 21 = 1311212120021 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1311212120021) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 50431235373 + ... + 50431235398.
It is an arithmetic number, because the mean of its divisors is an integer number (353018647702).
Almost surely, 21311212120023 is an apocalyptic number.
1311212120023 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
1311212120023 is a deficient number, since it is larger than the sum of its proper divisors (100862470785).
1311212120023 is a wasteful number, since it uses less digits than its factorization.
1311212120023 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 100862470784.
The product of its (nonzero) digits is 144, while the sum is 19.
Adding to 1311212120023 its reverse (3200212121131), we get a palindrome (4511424241154).
The spelling of 1311212120023 in words is "one trillion, three hundred eleven billion, two hundred twelve million, one hundred twenty thousand, twenty-three".
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