1311213131 has 2 divisors, whose sum is σ = 1311213132. Its totient is φ = 1311213130.

The previous prime is 1311213121. The next prime is 1311213133. The reversal of 1311213131 is 1313121131.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1311213131 is a prime.

It is a super-2 number, since 2×1311213131² = 3438559749813646322, which contains 22 as substring.

Together with 1311213133, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1311213133) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655606565 + 655606566.

It is an arithmetic number, because the mean of its divisors is an integer number (655606566).

Almost surely, 2^1311213131 is an apocalyptic number.

1311213131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311213131 is an equidigital number, since it uses as much as digits as its factorization.

1311213131 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 54, while the sum is 17.

The square root of 1311213131 is about 36210.6770304009. The cubic root of 1311213131 is about 1094.5218351081.

Adding to 1311213131 its reverse (1313121131), we get a palindrome (2624334262).

The spelling of 1311213131 in words is "one billion, three hundred eleven million, two hundred thirteen thousand, one hundred thirty-one".