1311213412221 has 4 divisors (see below), whose sum is σ = 1748284549632. Its totient is φ = 874142274812.

The previous prime is 1311213412151. The next prime is 1311213412343. The reversal of 1311213412221 is 1222143121131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 1311213412221 - 2⁹ = 1311213411709 is a prime.

It is a super-2 number, since 2×1311213412221² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1311213412191 and 1311213412200.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1311213612221) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 218535568701 + ... + 218535568706.

It is an arithmetic number, because the mean of its divisors is an integer number (437071137408).

Almost surely, 2^{1311213412221} is an apocalyptic number.

It is an amenable number.

1311213412221 is a deficient number, since it is larger than the sum of its proper divisors (437071137411).

1311213412221 is an equidigital number, since it uses as much as digits as its factorization.

1311213412221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 437071137410.

The product of its digits is 576, while the sum is 24.

Adding to 1311213412221 its reverse (1222143121131), we get a palindrome (2533356533352).

The spelling of 1311213412221 in words is "one trillion, three hundred eleven billion, two hundred thirteen million, four hundred twelve thousand, two hundred twenty-one".