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13112203121 is a prime number
BaseRepresentation
bin11000011011000110…
…00101011101110001
31020211210220221012122
430031203011131301
5203323210444441
610005040004025
7642634613303
oct141543053561
936753827178
1013112203121
115619551306
12265b300615
13130c6c8a94
148c5615973
1551b21734b
hex30d8c5771

13112203121 has 2 divisors, whose sum is σ = 13112203122. Its totient is φ = 13112203120.

The previous prime is 13112203109. The next prime is 13112203213. The reversal of 13112203121 is 12130221131.

13112203121 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 13096513600 + 15689521 = 114440^2 + 3961^2 .

It is a cyclic number.

It is not a de Polignac number, because 13112203121 - 210 = 13112202097 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 13112203121.

It is not a weakly prime, because it can be changed into another prime (13112203421) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6556101560 + 6556101561.

It is an arithmetic number, because the mean of its divisors is an integer number (6556101561).

Almost surely, 213112203121 is an apocalyptic number.

It is an amenable number.

13112203121 is a deficient number, since it is larger than the sum of its proper divisors (1).

13112203121 is an equidigital number, since it uses as much as digits as its factorization.

13112203121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 17.

Adding to 13112203121 its reverse (12130221131), we get a palindrome (25242424252).

The spelling of 13112203121 in words is "thirteen billion, one hundred twelve million, two hundred three thousand, one hundred twenty-one".