131122112333 has 4 divisors (see below), whose sum is σ = 138023276160. Its totient is φ = 124220948508.

The previous prime is 131122112309. The next prime is 131122112347. The reversal of 131122112333 is 333211221131.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 333211221131 = 23 ⋅14487444397.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-131122112333 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 131122112299 and 131122112308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (131122172333) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3450581885 + ... + 3450581922.

It is an arithmetic number, because the mean of its divisors is an integer number (34505819040).

Almost surely, 2^131122112333 is an apocalyptic number.

It is an amenable number.

131122112333 is a deficient number, since it is larger than the sum of its proper divisors (6901163827).

131122112333 is an equidigital number, since it uses as much as digits as its factorization.

131122112333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 6901163826.

The product of its digits is 648, while the sum is 23.

Adding to 131122112333 its reverse (333211221131), we get a palindrome (464333333464).

The spelling of 131122112333 in words is "one hundred thirty-one billion, one hundred twenty-two million, one hundred twelve thousand, three hundred thirty-three".