Base | Representation |
---|---|
bin | 11000011011000110… |
… | …01010011001011011 |
3 | 1020211210221221220212 |
4 | 30031203022121123 |
5 | 203323212121243 |
6 | 10005040241335 |
7 | 642635026223 |
oct | 141543123133 |
9 | 36753857825 |
10 | 13112223323 |
11 | 5619565501 |
12 | 265b31024b |
13 | 130c705034 |
14 | 8c561d083 |
15 | 51b21d318 |
hex | 30d8ca65b |
13112223323 has 4 divisors (see below), whose sum is σ = 13802340360. Its totient is φ = 12422106288.
The previous prime is 13112223259. The next prime is 13112223329. The reversal of 13112223323 is 32332221131.
13112223323 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 13112223323 - 26 = 13112223259 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (13112223329) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 345058490 + ... + 345058527.
It is an arithmetic number, because the mean of its divisors is an integer number (3450585090).
Almost surely, 213112223323 is an apocalyptic number.
13112223323 is a deficient number, since it is larger than the sum of its proper divisors (690117037).
13112223323 is an equidigital number, since it uses as much as digits as its factorization.
13112223323 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 690117036.
The product of its digits is 1296, while the sum is 23.
Adding to 13112223323 its reverse (32332221131), we get a palindrome (45444444454).
The spelling of 13112223323 in words is "thirteen billion, one hundred twelve million, two hundred twenty-three thousand, three hundred twenty-three".
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