Base | Representation |
---|---|
bin | 11101110100000101110101… |
… | …101111101000111010101110 |
3 | 122012021020110112211222212220 |
4 | 131310011311233220322232 |
5 | 114141304432143032342 |
6 | 1142513031143140210 |
7 | 36422216653213521 |
oct | 3564056557507256 |
9 | 565236415758786 |
10 | 131123032002222 |
11 | 38863a692163a7 |
12 | 12858632144666 |
13 | 5821b05c45a30 |
14 | 24545624c4bb8 |
15 | 1025c2707b5ec |
hex | 774175be8eae |
131123032002222 has 32 divisors (see below), whose sum is σ = 285993760174080. Its totient is φ = 39834845163360.
The previous prime is 131123032002203. The next prime is 131123032002229. The reversal of 131123032002222 is 222200230321131.
It is a junction number, because it is equal to n+sod(n) for n = 131123032002192 and 131123032002201.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131123032002229) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 10639642654 + ... + 10639654977.
It is an arithmetic number, because the mean of its divisors is an integer number (8937305005440).
Almost surely, 2131123032002222 is an apocalyptic number.
131123032002222 is an abundant number, since it is smaller than the sum of its proper divisors (154870728171858).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131123032002222 is a wasteful number, since it uses less digits than its factorization.
131123032002222 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 21279297728.
The product of its (nonzero) digits is 1728, while the sum is 24.
Adding to 131123032002222 its reverse (222200230321131), we get a palindrome (353323262323353).
The spelling of 131123032002222 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, thirty-two million, two thousand, two hundred twenty-two".
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