Base | Representation |
---|---|
bin | 10011000101001011011… |
… | …011111111101000010011 |
3 | 11122100111220210211122011 |
4 | 103011023123333220103 |
5 | 132440400021424440 |
6 | 2442212051323351 |
7 | 163506342445642 |
oct | 23051333775023 |
9 | 4570456724564 |
10 | 1311230654995 |
11 | 4660a9580548 |
12 | 1921605b0557 |
13 | 96857a50221 |
14 | 4766cd3b359 |
15 | 24194d769ea |
hex | 1314b6ffa13 |
1311230654995 has 4 divisors (see below), whose sum is σ = 1573476786000. Its totient is φ = 1048984523992.
The previous prime is 1311230654977. The next prime is 1311230655011. The reversal of 1311230654995 is 5994560321131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 1311230654995 - 25 = 1311230654963 is a prime.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 131123065495 + ... + 131123065504.
It is an arithmetic number, because the mean of its divisors is an integer number (393369196500).
Almost surely, 21311230654995 is an apocalyptic number.
1311230654995 is a deficient number, since it is larger than the sum of its proper divisors (262246131005).
1311230654995 is an equidigital number, since it uses as much as digits as its factorization.
1311230654995 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 262246131004.
The product of its (nonzero) digits is 874800, while the sum is 49.
The spelling of 1311230654995 in words is "one trillion, three hundred eleven billion, two hundred thirty million, six hundred fifty-four thousand, nine hundred ninety-five".
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