131123303101120 has 224 divisors, whose sum is σ = 348019265912832. Its totient is φ = 46653980160000.

The previous prime is 131123303101111. The next prime is 131123303101121. The reversal of 131123303101120 is 21101303321131.

It is a super-3 number, since 3×131123303101120³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Harshad number since it is a multiple of its sum of digits (22).

It is a junction number, because it is equal to n+sod(n) for n = 131123303101091 and 131123303101100.

It is not an unprimeable number, because it can be changed into a prime (131123303101121) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 39412905 + ... + 42610135.

Almost surely, 2^{131123303101120} is an apocalyptic number.

131123303101120 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131123303101120, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (174009632956416).

131123303101120 is an abundant number, since it is smaller than the sum of its proper divisors (216895962811712).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131123303101120 is a wasteful number, since it uses less digits than its factorization.

131123303101120 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3197511 (or 3197501 counting only the distinct ones).

The product of its (nonzero) digits is 324, while the sum is 22.

Adding to 131123303101120 its reverse (21101303321131), we get a palindrome (152224606422251).

The spelling of 131123303101120 in words is "one hundred thirty-one trillion, one hundred twenty-three billion, three hundred three million, one hundred one thousand, one hundred twenty".