13112401003 has 4 divisors (see below), whose sum is σ = 14121047248. Its totient is φ = 12103754760.

The previous prime is 13112400989. The next prime is 13112401007. The reversal of 13112401003 is 30010421131.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-13112401003 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (13112401007) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 504323103 + ... + 504323128.

It is an arithmetic number, because the mean of its divisors is an integer number (3530261812).

Almost surely, 2^13112401003 is an apocalyptic number.

13112401003 is a gapful number since it is divisible by the number (13) formed by its first and last digit.

13112401003 is a deficient number, since it is larger than the sum of its proper divisors (1008646245).

13112401003 is a wasteful number, since it uses less digits than its factorization.

13112401003 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1008646244.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 13112401003 its reverse (30010421131), we get a palindrome (43122822134).

The spelling of 13112401003 in words is "thirteen billion, one hundred twelve million, four hundred one thousand, three".