Base | Representation |
---|---|
bin | 111101000011110011… |
… | …0110010011101011101 |
3 | 110112110021011000021212 |
4 | 1322013212302131131 |
5 | 4122020233024242 |
6 | 140123152434205 |
7 | 12321243361322 |
oct | 1720746623535 |
9 | 415407130255 |
10 | 131124111197 |
11 | 50678162552 |
12 | 214b5248965 |
13 | c498a47ca1 |
14 | 64bc8c2b49 |
15 | 36268ad782 |
hex | 1e879b275d |
131124111197 has 2 divisors, whose sum is σ = 131124111198. Its totient is φ = 131124111196.
The previous prime is 131124111191. The next prime is 131124111203. The reversal of 131124111197 is 791111421131.
It is a balanced prime because it is at equal distance from previous prime (131124111191) and next prime (131124111203).
It can be written as a sum of positive squares in only one way, i.e., 117146014756 + 13978096441 = 342266^2 + 118229^2 .
It is a cyclic number.
It is not a de Polignac number, because 131124111197 - 218 = 131123849053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131124111191) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65562055598 + 65562055599.
It is an arithmetic number, because the mean of its divisors is an integer number (65562055599).
Almost surely, 2131124111197 is an apocalyptic number.
It is an amenable number.
131124111197 is a deficient number, since it is larger than the sum of its proper divisors (1).
131124111197 is an equidigital number, since it uses as much as digits as its factorization.
131124111197 is an evil number, because the sum of its binary digits is even.
The product of its digits is 1512, while the sum is 32.
The spelling of 131124111197 in words is "one hundred thirty-one billion, one hundred twenty-four million, one hundred eleven thousand, one hundred ninety-seven".
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