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1311242365564 = 221679712021563
BaseRepresentation
bin10011000101001100001…
…000101010101001111100
311122100112201211210111221
4103011030020222221330
5132440411021144224
62442213150323124
7163506544131355
oct23051410525174
94570481753457
101311242365564
114661051498aa
121921644b94a4
139685a2c0561
1447670708d2c
1524195ddb6e4
hex1314c22aa7c

1311242365564 has 24 divisors (see below), whose sum is σ = 2310793204608. Its totient is φ = 651023826480.

The previous prime is 1311242365453. The next prime is 1311242365571. The reversal of 1311242365564 is 4655632421131.

It is a super-2 number, since 2×13112423655642 (a number of 25 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1311242365564.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 362154 + ... + 1659409.

It is an arithmetic number, because the mean of its divisors is an integer number (96283050192).

Almost surely, 21311242365564 is an apocalyptic number.

It is an amenable number.

1311242365564 is a deficient number, since it is larger than the sum of its proper divisors (999550839044).

1311242365564 is a wasteful number, since it uses less digits than its factorization.

1311242365564 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2022705 (or 2022703 counting only the distinct ones).

The product of its digits is 518400, while the sum is 43.

Adding to 1311242365564 its reverse (4655632421131), we get a palindrome (5966874786695).

The spelling of 1311242365564 in words is "one trillion, three hundred eleven billion, two hundred forty-two million, three hundred sixty-five thousand, five hundred sixty-four".

Divisors: 1 2 4 167 334 668 971 1942 3884 162157 324314 648628 2021563 4043126 8086252 337601021 675202042 1350404084 1962937673 3925875346 7851750692 327810591391 655621182782 1311242365564